通过JAax将变量传递到PHP
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- <?php
- include('header.php');
- require_once('/homepages/9/d322999378/htdocs/spaincoastrealty/wordpress_en/wp-admin/includes/image.php');
- require_once("/homepages/9/d322999378/htdocs/spaincoastrealty/wordpress_en/wp-load.php");
- global $wpdb;
- global $posts;
- ?> <form id = "test" method = "post"> <div> <div class="control-group"> <label class="control-label" for="selectError">Site</label> <div class="controls"> <select name="sitechooser" id="sitechooser"> <option value="Site1" selected>Site1</option> <option value="Site2">Site2</option> </select> </div> </div> </div> <input type = "text" id = "site_value" value = "some text"> </form> <script>
- $(document).ready(function (e) {
- $('#sitechooser').change(function () {
- var selected = $("#sitechooser option:selected").text();
- if (selected == "Site1") {
- var id = $('#site_value').val();
- $.ajax({
- url: 'try.php',
- dataType: 'JSON',
- data: {id: id},
- success: function(data){
- alert(data);
- id = data.id;
- $('#id').text(id);
- }
- });
- }
- });
- });
- </script> <?php
- echo "id = ".$id;
- ?>
我想在php$id变量中获取id值.
我的代码中有什么错误吗?谢谢